# another vertors and oblique triangles problem

• Sep 14th 2006, 01:59 AM
danielwu
another vertors and oblique triangles problem
someone help on this can? pls.....
solve the given problems

in lifting a heavy piece of equipment from the mud, a cable from a crane exerts a vertical force of 6500N, and a cable from a truck exerts a force of 8300N at 10.0 degree above the horizontal. find the resultant of these forces.
• Sep 14th 2006, 04:53 AM
ThePerfectHacker
Quote:

Originally Posted by danielwu
someone help on this can? pls.....
solve the given problems

in lifting a heavy piece of equipment from the mud, a cable from a crane exerts a vertical force of 6500N, and a cable from a truck exerts a force of 8300N at 10.0 degree above the horizontal. find the resultant of these forces.

Let us draw a coordinate system.
With the origion of the point on which the two forces are applied.
The vertial force of 6500 N can be expressed in vector form as,
6500j.
The truck on the left with an 8300 N for at a 10 degree angle above the x-axis needs a polar angle conversion. The x-coordinate is 8300 cos (10) = 8174. The y-coordinate is 8300 sin (10) = 1441.
Thus, in vector form it can be expressed as,
8174i+8174j.

Now you add then and have a resultant.
• Sep 14th 2006, 12:37 PM
danielwu
Quote:

Originally Posted by ThePerfectHacker
Let us draw a coordinate system.
With the origion of the point on which the two forces are applied.
The vertial force of 6500 N can be expressed in vector form as,
6500j.
The truck on the left with an 8300 N for at a 10 degree angle above the x-axis needs a polar angle conversion. The x-coordinate is 8300 cos (10) = 8174. The y-coordinate is 8300 sin (10) = 1441.
Thus, in vector form it can be expressed as,
8174i+8174j.

Now you add then and have a resultant.

i got the answers behind the book as 11000N, 44 degree above horizontal

but by doing your method i couldnt understand and get the correct answers.
pls help me understand further. thanks