I'm currently stuck on this question:

Q: A uniform chain of length l, total mass m and containing many links, is held at one end over a table with the other end just touching the table top.

a)The chain is released and falls freely. What is the speed of the falling section of the chain at time t after release? What is now the force between the links?

b) Work out the increment of mass

, which hits the table in the increment of time

. Find the corresponding change in momentum and hence the instantaneous force on the table.

c) What is the total force acting on the table as a function of time? Show that the maximum value of the total force is three times the total weight of the chain.

I have no idea as to how to approach the question, other than for part a) the speed of the falling section of chain is: v=u+at, u=0 and v=at, but don't know if that's right.

Any help would be hugely appreciated.