I'm currently stuck on this question:
Q: A uniform chain of length l, total mass m and containing many links, is held at one end over a table with the other end just touching the table top.
a)The chain is released and falls freely. What is the speed of the falling section of the chain at time t after release? What is now the force between the links?
b) Work out the increment of mass , which hits the table in the increment of time . Find the corresponding change in momentum and hence the instantaneous force on the table.
c) What is the total force acting on the table as a function of time? Show that the maximum value of the total force is three times the total weight of the chain.
I have no idea as to how to approach the question, other than for part a) the speed of the falling section of chain is: v=u+at, u=0 and v=at, but don't know if that's right.
Any help would be hugely appreciated.