Hey guys, I am stuck on this question. Can anyone give me some hints? I know the sum of the x and y components have to equal zero but I don't know how to find "the minimum". Here is the problem
So minimum F3 has zero horizontal component,
(F3)cos(alpha) = 0 -----(i)
For Eq.(i) to be true, if F3 is not zero, the cos(alpha) should be zero, so,
cos(alpha) = 0
alpha = arccos(0) = 90 degrees, for minimum F3 ---------answer.
And, minimum F3 = 137sin(30deg) = 68.5 newtons ------answer.