# Gen Chem: theoretical yield

• September 26th 2008, 10:30 AM
viet
Gen Chem: theoretical yield
Quote:

compute the theoretical yield of product (in moles) for each of the following initial amounts of reactants.
$2 Mn(s) + 2 O_2(g) > 2MnO_2(s)$
a) 5 mol Mn, 5 mol $O_2$
b) 4 mol Mn, 7 mol $O_2$
c) 28.5 mol Mn, 44.8 mol $O_2$

i'm not sure how to solve this, the examples in the book had it in grams in stead of moles.
• October 1st 2008, 02:02 PM
Greengoblin
surely since $MnO_2$ needs only one mole of $Mn$ and one mole of $O_2$ then the number of moles of $MnO_2$ is equal to the lowest number of moles of the two reactants? So a = 5 mol, b = 4 mol, c = 28.5 mol ? Then the remaining reactants goes unreacted?

edit: Why doesn't \mbox work?