Originally Posted by
myoplex11 evaluate the commutator [-d^2 / dx^2 , x] f (x)
can anyone please check my work thanks.
[-d^2 / dx^2 , x] f (x) = -2f '(x) -xf "(x) + -xf "(x)
[-d^2 / dx^2 , x] f (x) = -2f '(x) = -2 (d/dx (f(x))
[-d^2 / dx^2 , x] = -2 d/dx