[x, i d/dx] what is the value of this commutator can anyone check my work please: [x, i d/dx] = ixf '(x) - if (x) - ixf '(x) [x, i d/dx] f(x) = -if(x) [x, i d/dx] = -i
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Originally Posted by myoplex11 [x, i d/dx] what is the value of this commutator can anyone check my work please: [x, i d/dx] f(x) = ixf '(x) - if (x) - ixf '(x) Mr F says: The red f(x) needs to be included. [x, i d/dx] f(x) = -if(x) [x, i d/dx] = -i Looks fine.
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