force on a pulley???

a particle of mass 10kg is at rest on a plane inclined at an angle tan-1(3/4) to the horizontal.contact is rough with a coefficient of friction of 0.25.it is connected by means of a light inextensible string passing over a smooth,fixed pulley to a second particle of mass 20kg hanging freely.

(i) i worked the acceleration out to be 2g/5 (g=9.8)

(ii) i then worked out the tension in the string to be 12g Newtons

(iii)FIND THE FORCE ON THE PULLEY? how do i work this out? what is the formula?

can someone please solve part (iii).

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Originally Posted by Im doin My best!

a particle of mass 10kg is at rest on a plane inclined at an angle tan-1(3/4) to the horizontal.contact is rough with a coefficient of friction of 0.25.it is connected by means of a light inextensible string passing over a smooth,fixed pulley to a second particle of mass 20kg hanging freely.

(i) i worked the acceleration out to be 2g/5 (g=9.8)

(ii) i then worked out the tension in the string to be 12g Newtons

(iii)FIND THE FORCE ON THE PULLEY? how do i work this out? what is the formula?

can someone please solve part (iii).

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The force acting on the pulley will be the vector sum of the two tensions acting at the pulley. So one tension is pulling straight down and a tension of equal magnitude is pulling down the slope.

-Dan