Quote Originally Posted by uberjeep View Post
This is what I've got:
H=1.70
Angular velocity (omega)=1 degree/240 seconds (from 360degrees/24 hrs). So the angle @ is 0.4625 degrees for T=11.1s

cos@ = r/r+h
therefore r = (cos@)(r+h)
r = rcos@ + hcos@
r-rcos@ = hcos@
r(1-cos@) = hcos@
r = (hcos@)/(1-cos@)
Substituting h=1.7m & @=0.4625, cos@ = 0.99999967420217
and r = 5217958.1618m
=5218km
The theta you quote is wrong it has the decimal point in the wrong place but your calculation appears to have used the correct value..

CB