A man is walking in the north-east direction and wind appears to blow from north. If the man doubles his speed, wind appears at angle arccot 2 east of north. Find the actual direction of the wind.

The wind comes from the west. You can check that it works; anyway, here is how I found this out:
Let us denote byand
the respective speeds of the wind and the man, in an orthonormal basis
(E for east, N for north). Since the man goes NE, both components of
are equal to some positive
.
We know that the relative speed, i.e. the vector, is along the N direction, hence the E component is zero:
.
Then we are told that the vectoris (positively) colinear with
. This is the content of the statement about "arccot 2" (draw a right triangle with perpendicular sides of length 1 and 2; the least angle measures
). As a consequence,
. Replace
by
(as seen above), to get
, hence
.
Finally,(the same
as in
), and
, which means that the wind comes from the west.
I hope my explanations are clear.
Laurent.