BIG warning on this one: Watch your units!Originally Posted byCelia

Assume that air is an ideal gas (not too bad an approximation.)

We need pressures. 15 m below the surface of the water and P2 = P0 (at the surface), where P0 = 1.01 x 10^5 Pa. (I'm going to presume we can take .) Thus P1 = 157100 Pa.

V1 = 2.0 cm^3 = 2.0 x 10^(-6) m^3.

Finally, T1 = 273 K + 7 K = 280 K and T2 = 273 K + 20 K = 293 K.

I get V2 = 32.553 x 10^(-6) m^3 = 33 cm^3.

-Dan