If 2.4 m3 of a gas initially at STP is compressed to 1.6 m3 and its temperature raised to 30oC, what is the final pressure?

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- Jul 31st 2006, 04:30 PM #1

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- Jul 31st 2006, 04:37 PM #2Originally Posted by
**pocahontas**

$\displaystyle \frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

Where T is in the absolute (Kelvin) temperature scale.

At STP, T1 = 273 K and P1 = 1.01 x 10^5 Pa. And V1 = 2.4 m^3.

We know V2 = 1.6 m^3 and T2 = 273 K + 30 K = 303 K.

So $\displaystyle P_2 = \frac{P_1V_1}{T_1} \cdot \frac{T_2}{V_2} = 168148.35 \, Pa \, = 1.7 \times 10^5 \, Pa$

-Dan