A circular steel plate of radius 0.10 m is cooled from 350oC to 20oC. By what percentage does the plate's area decrease?
The coefficient of linear expansion of steel is $\displaystyle \alpha=12 \times 10^{-6}/^{\circ} K$, so in coolling by $\displaystyle \Delta T=330^{\circ} C\ (=330^{\circ} K)$ the radius shrinks from $\displaystyle 0.1\ \mbox{m}$ to $\displaystyle 0.1-0.1\times \alpha \times \Delta T$ or by a fraction $\displaystyle \alpha \times \Delta T $, so the area reduces by about twice this as a fraction or $\displaystyle 2 \times \alpha \times \Delta T\approx 2 \times 12 \times 10^{-6} \times 330 = 0.00792 $, or $\displaystyle 0.792 \%$.Originally Posted by babygirl
RonL