I don't know if this part of the forum is the appropriate place for this kind of a question but I think you guys can still help solve my problem.
My Chemistry teacher asked me to find at least two values of x for the expression/equation rather
2^x=4x without using a calculator or without relying much on a calculator.
So I used common sense and say that x=4 and I got stuck from there.
This is what I did: 2^x=2^2(x).By just looking at it, I concluded that x must be 4 for the two sides to be equal. From here, I don't know where to go. Is there a formula(good formula maybe) to solve this kind of a question? What can I do to find the other values of x?
Your help will be highly appreciated.
Thanks a lot.I will report the two solutions to him and ask him to solve the rest without using any mechanical aid hehehe. Just before, I go ...why do you think 1/3 is a transcendental number?
Originally Posted by CaptainBlack
Thanks once more.
It's not 1/3 that I think transcendental but the solution near it at approx 0.3099..
Originally Posted by McCoy
When I calculate this to 15 significant figures and feed it into the inverse symbolic calculator it reports no hits.
(also mixed transcendental/algebraic equations charateristicly have transcendental roots, only under special conditions are the roots integer, rational or algebraic numbers).