Non uniform motion in a circle
Another question i cant get my head around (this ones a bit long):
1) express each force in vector form
2)Derive equation of motion for particle p1 and p2
3)write down distance p2 has fallen after time t and deduce magnitude of acceleration of p2 as r*theta where theta is magnitude of angular acceleration
4) show that
Magnitude of angular acceleration = g(2-cos(theta))/3R
5) Show that magnitude of normal reaction of the cyclinder on P1 is
Non-Uniform Motion in a circle
I am a bit confused by this question(see attached image). This has been posted before but im not any further forward. My problems are:
P1 - has this got the following forces acting on it: Weight, Tension, and Natural reaction force?
and thus does the equation of motion end up as:
mr''= -|T|er - (mgcos a)er - (mgsin a)eo + |N|er
where er and eo are the radial and tangential components respectively
Then is it a case of gathering the similar terms and resolving in the er direction to get:
ml0'^2 = mg cos a - |T|
P2 - is this just experiencing the tension of the string and its own weight?
Thanks in advance[IMG]file:///C:/DOCUME%7E1/Paul/LOCALS%7E1/Temp/moz-screenshot-5.jpg[/IMG]
Sorry for double post - dont know what happened there!!!