A 75-Kg

**Celia** · July 25th 2006, 04:30 PM

A 75-Kg athlete does a single-hand handstand. If the area of the hand in contact with the floor is 125 cm2, what pressure is exerted on the floor?

**CaptainBlack** · July 25th 2006, 07:36 PM

Originally Posted by Celia

A 75-Kg athlete does a single-hand handstand. If the area of the hand in contact with the floor is 125 cm2, what pressure is exerted on the floor?

The pressure is the force per unit area. If the mass of the athlete is $75\ \mathrm{kg}$
then the gravitational force on him is $75.g \mbox{ Newtons} \approx 750 \mbox{ N}$ . The area
is $125 \mbox{ cm^2} \approx 0.0125 \mbox{ m^2}$ .

Therefore the pressure on his hand is $750/0.0125 \mbox{ N/m^2} = 60000 \mbox{ Pascal}$ .

RonL

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