A 0.20-kg billiard ball traveling at a speed of 15 m/s strikes the side rail of a pool table at an angle of 60o. If the ball rebounds at the same speed and angle, what is the change in its momentum?

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- Jul 21st 2006, 10:26 AMMohychaA 0.20-kg billiard
A 0.20-kg billiard ball traveling at a speed of 15 m/s strikes the side rail of a pool table at an angle of 60o. If the ball rebounds at the same speed and angle, what is the change in its momentum?

- Jul 21st 2006, 10:41 PMCaptainBlackQuote:

Originally Posted by**Mohycha**

collision. If we take positive upwards and to the right the initial velocity of

the ball is:

$\displaystyle 15\ \left( \frac{1}{2\sqrt{3}},\frac{1}{2}\right)$,

and the final velocity is:

$\displaystyle 15\ \left( \frac{1}{2\sqrt{3}},-\frac{1}{2}\right)$.

Therefore the change in velocity is:

$\displaystyle 15\ (0,-1)$,

and (as the mass of the ball does not change) the change in momentum is:

$\displaystyle 0.2\times 15\ (0,-1)=(0,-3)$.

RonL