# Spring force!

• Jul 17th 2006, 09:38 PM
Candy
Help me!
A 200-g mas attached to the end of a spring causes it to stretch 5.0 cm. If another 200-g mass is added to the spring, the potential energy of the spring will be.
• Jul 17th 2006, 09:45 PM
malaygoel
Quote:

Originally Posted by Candy
A 200-g mas attached to the end of a spring causes it to stretch 5.0 cm. If another 200-g mass is added to the spring, the potential energy of the spring will be.

we have,initially, $mg=k(5cm)$(spring is assumed to be massless)
You could clculate k(spring constant) from it
Finally, we have $2mg=kx$
Calculate x
Potential energy= $\frac{1}{2}kx^2$

Keep Smiling
Malay