weber number - dimensional analysis

can someone check this for me?


weber number = density*velocity^2*length/surface tension

find dimensions of surface tension.

density= ML-3
speed = [LT-1]^2
Length = L

so

[ML^-3]*[LT^-1]^2*[L]

= MLT

So for weber number to be dimensionless the surface tension has to cancel out MLT and therefore also has dimensions MLT.

Quote:

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Originally Posted by thermalwarrior

can someone check this for me?


weber number = density*velocity^2*length/surface tension

find dimensions of surface tension.

density= ML-3
speed = [LT-1]^2
Length = L

so

[ML^-3]*[LT^-1]^2*[L]

= MLT

So for weber number to be dimensionless the surface tension has to cancel out MLT and therefore also has dimensions MLT.

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-Dan