Immediate Mechanics Help Required!!!

please visit this link:
http://www.meidistance.co.uk/npapers/m201ja.pdf
and see question 1(iv), the mark scheme answer is on page 7 but i need someone to explain how 24.6m/s was obtained.

Also, on page 8, how do you find 3.45 and 1.82 from those vectors on the top of the page? Thanks,

AAKhan07

Quote:

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Originally Posted by AAKhan07

please visit this link:
http://www.meidistance.co.uk/npapers/m201ja.pdf
and see question 1(iv), the mark scheme answer is on page 7 but i need someone to explain how 24.6m/s was obtained.

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Consevation of linear momentum. The initial momentum of the system is kg m/s the momentum of the component is kg m/s. So the momentum of the remaining two parts is the initial momentum of the system plus , so:



RonL

Quote:

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Originally Posted by AAKhan07

Also, on page 8, how do you find 3.45 and 1.82 from those vectors on the top of the page? Thanks,

AAKhan07

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Combine the vectors on the left into a single vector, then equate components on the right and left to get an equation for x and an equation for y. Solve these equations.

RonL