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Math Help - Theoretical yield

  1. #1
    Member Jonboy's Avatar
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    Theoretical yield

    I think that the theoretical yield is the max amount of the products that can be formed. But I don't see how to find it.

    The problem that is stumping me is this:

    Given the equation Cu_2 + O_2 \to 2Cu + SO_2, what is the theoretical yield of SO_2 if 8.20 g of 0_2 are used ?

    Will someone simply and clearly explain how to go about solving this?
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  2. #2
    o_O
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    You have 8.20 g of O_{2} so we must "convert" it into terms of SO_{2}. However, remember that a chemical reaction is representative of each species in moles. So that is where we will start off with:

    \text{8.20 g } O_{2} \times \frac{\text{1 mol } O_{2} }{\text{32.00 g }O_{2} } = \text{0.25625 mol } O_{2}

    Now, we know that for every mole of SO_{2} produced, 1 mole of O_{2} was used up. So we have a 1-1 ratio.

    \text{0.25625 mol } O_{2} \times \frac{\text{1 mol } SO_{2} }{\text{1 mol } O_{2} } = \text{0.25625 mol } SO_{2} \text{ produced}

    Note how I set up the ratio so that the units "mol O_{2}" cancels out. That is pretty much the key in solving stoichiometry questions.

    So you have the moles of SO_{2} produced. Now all that is left is converting it into terms of grams and that should be your theoretical yield.
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  3. #3
    Member Jonboy's Avatar
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    that makes complete sense! thank you.
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