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Math Help - Number of Moles

  1. #1
    Member Jonboy's Avatar
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    Number of Moles

    Given: 2KClO_{3}(s) + heat \to 2KCl(s) + 3O_{2}

    How many moles of O_2 form as 3.0 mol of KClO_{3} are totally consumed?

    I see that the ratio between O_2 and KClO_{3} is 3 : 2.

    So since KClO_{3} is 3.0 mol, then I figured O_2 must be \boxed{4.5\,moles}

    Is this correct?
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  2. #2
    o_O
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    \text{3.0 mol } KClO_{3} \times \frac{\text{3 mol } O_{2}}{\text{2 mol } KClO_{3} } = \text{4.5 mol } O_{2}

    Looks good to me.
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