1a.) Calculate the

using the equation below at

respectively, assuming that particle has an energy of

, and has a width of the barrier

.

Equation:

b.) Using the same equation, calculate

at

, respectively, if

and

.

c.) Explain why the above happens in a.) and b.). Explain the physical meaning of

.

d.) Suppose that it's a larger system (that is, it's a calssical system where

and

are large) with

- explain if it's possible to locate the particle in region

. Why is this the case?

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So I know

but I have to get the units correct for a and b and I'm awful at units in physics. Then I guess I'll be able to see a trend if we have the ratio of transmitted current to incident current.

For d.), I'm going with "no". I say this, because in my book it says "there is a finite probability for the particle to be inside the classically forbidden barrier region where its kinetic energy is zero, but the point is that nobody can "see" a particle actually go through a classically forbidden region. Particle detectors can detected only objects of kinetic energy greater than zero; if you insert a detector inside the barrioer to see the particle, you are not only making a hole in the potential, but also in your ojbective, because the ojbect will no longer belong to a classically forbidden region where you wanted to find it."

Thanks!