1a.) Calculate the using the equation below at respectively, assuming that particle has an energy of , and has a width of the barrier .
b.) Using the same equation, calculate at , respectively, if and .
c.) Explain why the above happens in a.) and b.). Explain the physical meaning of .
d.) Suppose that it's a larger system (that is, it's a calssical system where and are large) with - explain if it's possible to locate the particle in region . Why is this the case?
So I know but I have to get the units correct for a and b and I'm awful at units in physics. Then I guess I'll be able to see a trend if we have the ratio of transmitted current to incident current.
For d.), I'm going with "no". I say this, because in my book it says "there is a finite probability for the particle to be inside the classically forbidden barrier region where its kinetic energy is zero, but the point is that nobody can "see" a particle actually go through a classically forbidden region. Particle detectors can detected only objects of kinetic energy greater than zero; if you insert a detector inside the barrioer to see the particle, you are not only making a hole in the potential, but also in your ojbective, because the ojbect will no longer belong to a classically forbidden region where you wanted to find it."