I know Projectile motion is physics in nature but i am having problems with the mathematical mechanics and any help would be greatly appreciated,
A fighter pilot blows up a artillery dump. Diving at an angle of 53degrees below the horizon, the pilot releases a bomb at an altitude of 750m. The bomb hits the target 5.0s after being released.
What is the velocity of the bomber?
So i enter this into the equation d= vt - (1/2)gt^2 yet i get a negative number which to me doesnt make sense.
"Did you consider that the equation for and are differnt"
Yes. I should have defined all my variables a little better. The d = distance in the y direction (in metres), the v = initial velocity of the bomber (metres/second), t = time (seconds)
"...I hope I am not making a fool out of myself lol"
It was a valid question, thanks for your help.
Define a coordinate system where the origin is on the ground directly below the plane when the bomb is dropped. I'm taking +x in the direction the plane is traveling and +y straight up.
We know for the bomb that
.... ?
.... ?
....
.... ?
where are the positions, etc. at time t = 5.0 s, and is the speed the plane is moving at as it drops the bomb.
We have three main equations:
See if that helps. (The basic idea is that we have the motion equations independent of each other in each coordinate direction.)
-Dan