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Math Help - Mechanics 3, Further Kinamatics Question

  1. #1
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    Mechanics 3, Further Kinamatics Question

    Could someone answer this question for me please, I have been attempting it all day long, with no luck, and its simply frustrating me now .

    Or if you dont want to answer it, could you simply give me a hint on how to solve it .

    The question is on the jpeg below.
    Attached Thumbnails Attached Thumbnails Mechanics 3, Further Kinamatics Question-maths-question.jpg  
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  2. #2
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    Quote Originally Posted by Koudoo View Post
    Could someone answer this question for me please, I have been attempting it all day long, with no luck, and its simply frustrating me now .

    Or if you dont want to answer it, could you simply give me a hint on how to solve it .

    The question is on the jpeg below.
    Since a = dv/dt,
    v - u = \int_0^t \frac{1}{(T + t_0)^3}~dT

    So let y = T + t_0 \implies dy = dT

    v - u = \int_{t_0}^{t + t_0} \frac{1}{y^3}~dy

    You finish this.

    -Dan
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  3. #3
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    You really shouldn't post a question on two websites, it is considered rude.

    M3, Further Kinamatics Question (Edexcel) - The Student Room
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