# Thread: Mechanics 3, Further Kinamatics Question

1. ## Mechanics 3, Further Kinamatics Question

Could someone answer this question for me please, I have been attempting it all day long, with no luck, and its simply frustrating me now .

Or if you dont want to answer it, could you simply give me a hint on how to solve it .

The question is on the jpeg below.

2. Originally Posted by Koudoo
Could someone answer this question for me please, I have been attempting it all day long, with no luck, and its simply frustrating me now .

Or if you dont want to answer it, could you simply give me a hint on how to solve it .

The question is on the jpeg below.
Since a = dv/dt,
$\displaystyle v - u = \int_0^t \frac{1}{(T + t_0)^3}~dT$

So let $\displaystyle y = T + t_0 \implies dy = dT$

$\displaystyle v - u = \int_{t_0}^{t + t_0} \frac{1}{y^3}~dy$

You finish this.

-Dan

3. You really shouldn't post a question on two websites, it is considered rude.

M3, Further Kinamatics Question (Edexcel) - The Student Room