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Thread: solve for the resistance of each resistor.

  1. March 29th 2008, 12:04 PM #1
    polakio92
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    solve for the resistance of each resistor.

    when two resistors of resistances R(1) and R(2) (the numbers are the subscripts) are connected in parallel, their combined resistance is
    R(1) R(2) / R(1) + R(2). two resistors are found to have a combined resistance of 10 ohms (thats just a variable, im assuming) when connected in series, and 2 ohms when connected in parallel. what is the resistance of each? it would be best to use X as the variable. thanks!
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  2. March 29th 2008, 12:32 PM #2
    Peritus
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    \left\{ \begin{gathered}<br /> \left( {\frac{1}<br /> {{R_1 }} + \frac{1}<br /> {{R_2 }}} \right)^{ - 1} = 2 \hfill \\<br /> R_1 + R_2 = 10 \hfill \\ <br /> \end{gathered} \right.<br />

    two equations in two unknowns...
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  3. March 29th 2008, 01:04 PM #3
    polakio92
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    Quote Originally Posted by Peritus View Post
    \left\{ \begin{gathered}<br /> \left( {\frac{1}<br /> {{R_1 }} + \frac{1}<br /> {{R_2 }}} \right)^{ - 1} = 2 \hfill \\<br /> R_1 + R_2 = 10 \hfill \\ <br /> \end{gathered} \right.<br />

    two equations in two unknowns...

    well how would i solve that?
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  4. March 29th 2008, 01:07 PM #4
    Peritus
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    for example you could isolate R1 from the s3econd equation and plug it into the first...
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  5. March 29th 2008, 01:12 PM #5
    polakio92
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    Quote Originally Posted by Peritus View Post
    for example you could isolate R1 from the s3econd equation and plug it into the first...
    but what about then the two are connected in parallel it is 2 ohms?
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  6. March 29th 2008, 01:15 PM #6
    polakio92
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    Quote Originally Posted by polakio92 View Post
    but what about then the two are connected in parallel it is 2 ohms?
    nevermind, u wrote that in in the original equation. sorry
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