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Thread: Low pass filter

  1. #16
    Junior Member
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    i get x = -9.872(10^8) + 2.962(10^6)j

    and x =-9.872(10^8) - 2.962(10^6)j

    wrong?
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  2. #17
    Junior Member
    Joined
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    Quote Originally Posted by Peritus View Post
    you can easily verify that the passband gain is 0db thus we are interested in finding the frequency in which the gain of the transfer function is -6db:

    <br />
20\log _{10} \left| {H_{out} \left( {jw} \right)} \right| =  - 6

    solve for w...
    <br />
20\log _{10} \left| {H_{out} \left( {jw} \right)} \right| =  - 6

    is the same as

    |H|=10^(-6/20)?
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  3. #18
    Senior Member Peritus's Avatar
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    yes
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