Thread: transformer current in primary coil

A step-down transformer (turns ratio = 1:8) is used with an electric train to reduce the voltage from the wall receptacle to a value needed to operate the train. When the train is running, the current in the secondary coil is 1.9 A.

What is the current in the primary coil?
in Amperes


if the formula for current in the secondary coil is: A * (ratio of primary coil/secondary coil) = current

then why can't we just use A* 1/8 = 1.9

multiply by 8 and get the amps for the first coil which is 15.2 A

Originally Posted by rcmango

A step-down transformer (turns ratio = 1:8) is used with an electric train to reduce the voltage from the wall receptacle to a value needed to operate the train. When the train is running, the current in the secondary coil is 1.9 A.

What is the current in the primary coil?
in Amperes
if the formula for current in the secondary coil is: A * (ratio of primary coil/secondary coil) = current

then why can't we just use A* 1/8 = 1.9
multiply by 8 and get the amps for the first coil which is 15.2 A

I hope this reply doesn't come too late.

are the turns in the primary or secondary coils.
are the voltages in the primary or secondary coils.
are the currents in the primary or secondary coils.
are the electrical energies in the primary or secondary coils.

Then you know:



You know by the law of conservation of energy that

. That means:

.

With your problem:

. And therefore you get:

. Plug i the value you know and solve for .

I've got

Okay, I see that I had my ratio incorrect, should be the reciprocal of what I have there. 8/1 instead of the other way i had it. Also, the Current I was using was correct.

Thanks for the help, I knew I was close, and it wasn't major.

Also, I got it in time to help me, thanks very much for the explanation!