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Thread: [SOLVED] speed & velocity

  1. #1
    cst301
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    Unhappy [SOLVED] speed & velocity

    Using standard eq. v=s/t can a vehicle accelerate to a speed of 114m/hr in a distance of .9tenth of a mile.
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  2. #2
    Super Member Aryth's Avatar
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    Well of course it's possible.

    First we have the following information:

    $\displaystyle \text{Initial Speed }= 0 \frac{m}{hr}$
    $\displaystyle \text{Final Speed }= 114 \frac{m}{hr}$
    $\displaystyle \text{Distance }= 0.9 m$

    According to the standard equation:

    $\displaystyle v = \frac{s}{t}$

    Plug-n-chug:

    $\displaystyle 114 = \frac{0.9}{t}$

    $\displaystyle 114t = 0.9$

    $\displaystyle t = \frac{0.9}{114}$

    $\displaystyle t = 0.008 hrs$

    It is possible to accelerate to that speed, in fact, it would take the same amount of time as specified above.

    Now, we know the change in velocity was 114 $\displaystyle \frac{m}{hr}$ so we have another standard equation:

    $\displaystyle a = \frac{v}{t}$

    It's similar to the speed formula, but it is changed around for acceleration:

    $\displaystyle a = \frac{114}{0.008}$

    $\displaystyle a = 14250 \frac{m}{hr^2}$

    That is the acceleration you must have in order to attain the velocity in the time allotted over the distance allotted.
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