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Math Help - Applications of Dot Product

  1. #1
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    Applications of Dot Product

    A crate with a weight of 57 N rests on a frictionless ramp inclined at an angle of 30 degrees to the horizontal. What force must be applies at an angle of 20 degrees to the ramp so that the crate remains at rest?

    I've drew the diagram and I don't know what to do after this:


    I know the formula to use is "u (dot) v = |u||v|cosx"

    The answer to this problem is 28.5 N and 30.3 N.

    Can you please show me a step by step solution to get the answer?
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  2. #2
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    Quote Originally Posted by Macleef View Post
    A crate with a weight of 57 N rests on a frictionless ramp inclined at an angle of 30 degrees to the horizontal. What force must be applies at an angle of 20 degrees to the ramp so that the crate remains at rest?

    I've drew the diagram and I don't know what to do after this:


    I know the formula to use is "u (dot) v = |u||v|cosx"

    The answer to this problem is 28.5 N and 30.3 N.

    Can you please show me a step by step solution to get the answer?
    I've attached a sketch with all the forces acting on the solid:

    F_w = \text{weight}
    F_d = \text{downhill force}
    F_u = \text{uphill force}
    F_p = \text{force to pull}

    | \overrightarrow{F_d} | =| \overrightarrow{ F_w} | \cdot \cos(60^\circ) = 28.5\ N

     \overrightarrow{F_u} = -| \overrightarrow{ F_d}

    |\overrightarrow{F_u}| = |\overrightarrow{F_p}| \cdot \cos(20^\circ)~\implies~ |\overrightarrow{F_p}| = \frac{|\overrightarrow{F_u}|}{\cos(20^\circ)}\appr  ox 30.329\ N
    Attached Thumbnails Attached Thumbnails Applications of Dot Product-kraft_schiefebene.gif  
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  3. #3
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by earboth View Post
    I've attached a sketch with all the forces acting on the solid:

    F_w = \text{weight}
    F_d = \text{downhill force}
    F_u = \text{uphill force}
    F_p = \text{force to pull}

    | \overrightarrow{F_d} | =| \overrightarrow{ F_w} | \cdot \cos(60^\circ) = 28.5\ N

     \overrightarrow{F_u} = -| \overrightarrow{ F_d}

    |\overrightarrow{F_u}| = |\overrightarrow{F_p}| \cdot \cos(20^\circ)~\implies~ |\overrightarrow{F_p}| = \frac{|\overrightarrow{F_u}|}{\cos(20^\circ)}\appr  ox 30.329\ N
    what is F_n?
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  4. #4
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    Quote Originally Posted by Jhevon View Post
    what is F_n?
    sorry I forgot to mention:

    F_n = \text{normal force acting perpendicularly at the surface of the inclined plane}
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