1) Determine the amount of heat needed to turn 500g of ice in a 100g aluminum pan into steam.

2) What will be the phase of 1 liter of water in a 200g copper pot if it is placed in a coolant that absorbs 100,000J of heat?

3) How much heat is required to turn 50g of ice with temperature of -50 C to steam at 150 C?

Specific Heat:

Water = 4180 J/kg*K or 1.000 cal/g*C

Copper = 392 J/kg*K or 0.093 cal/g*C

Aluminum = 895 J/kg*K or 0.214 cal/g*C

Latent Heat:

= Heat of fusion

Water = $\displaystyle 3.34 * 10^5 J/kg$ or $\displaystyle 80 cal/g$

Copper = $\displaystyle 2.05 * 10^5 J/kg$ or $\displaystyle 48.9 cal/g$

Aluminum = $\displaystyle 3.76 * 10^5 J/kg$ or $\displaystyle 89.9 cal/g$

= Heat of vaporization

Water = $\displaystyle 22.6 * 10^5 J/kg$ or $\displaystyle 540 cal/g$

Copper = $\displaystyle 48 * 10^5 J/kg$ or $\displaystyle 1150 cal/g$

Aluminum = $\displaystyle 113.71 * 10^5 J/kg$ or $\displaystyle 2717.7 cal/g$