Two forces P and Q act on a particle. The force P has magnitude 7N and acts due north. The resultant of P and Q is a force of magnitude 10N acting in a direction with bearing 120 degrees. Find
i) the magnitude of Q
ii) the direction of Q, giving your answer as a bearing.
any help would be much appreciated, thanks
Here is another attempt:
1. draw a rough sketch
2. You can calculate the dotted green line by Cosine rule. The length of this line correspond with the magnitude of Q:
3. To calculate the bearing of Q you have to add the angle to the 120° = bearing of the resultant force R:
This will give you
And therefore the bearing of Q is 144.182°