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Thread: Limits with taylor

  1. #1
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    Limits with taylor

    Where do i get wrong?
    The limit is supposed to be equal to 0
    I'm getting out of my mind ><

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  2. #2
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    Re: Limits with taylor

    $\displaystyle \text{Log}\left(1+x+\frac{x^2}{2}\right)=x-\frac{x^3}{6}+\text{...}$
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  3. #3
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    Re: Limits with taylor

    Quote Originally Posted by Idea View Post
    $\displaystyle \text{Log}\left(1+x+\frac{x^2}{2}\right)=x-\frac{x^3}{6}+\text{...}$
    How do i read what u wrote in the answer? Btw thx for answering... I read like {Log}\left(1+x etc..)
    I mean how do i translate it? ^^

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  4. #4
    MHF Contributor MarkFL's Avatar
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    Re: Limits with taylor

    Quote Originally Posted by domy7997 View Post
    How do i read what u wrote in the answer? Btw thx for answering... I read like {Log}\left(1+x etc..)
    I mean how do i translate it? ^^
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  5. #5
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    Re: Limits with taylor

    Are you saying you do not understand what "log" means?
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  6. #6
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    Re: Limits with taylor

    Quote Originally Posted by HallsofIvy View Post
    Are you saying you do not understand what "log" means?
    Solved. I have just to open the conversation through the web.

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