1. ## Limits with taylor

Where do i get wrong?
The limit is supposed to be equal to 0
I'm getting out of my mind ><

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2. ## Re: Limits with taylor

$\displaystyle \text{Log}\left(1+x+\frac{x^2}{2}\right)=x-\frac{x^3}{6}+\text{...}$

3. ## Re: Limits with taylor

Originally Posted by Idea
$\displaystyle \text{Log}\left(1+x+\frac{x^2}{2}\right)=x-\frac{x^3}{6}+\text{...}$
I mean how do i translate it? ^^

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4. ## Re: Limits with taylor

Originally Posted by domy7997
I mean how do i translate it? ^^
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5. ## Re: Limits with taylor

Are you saying you do not understand what "log" means?

6. ## Re: Limits with taylor

Originally Posted by HallsofIvy
Are you saying you do not understand what "log" means?
Solved. I have just to open the conversation through the web.

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