# Thread: cars on road

1. ## cars on road

can someone help me with question 8bii
i tried to solve this by 450-16t=200+20t t=4.16 the right answer is t =6.94

2. ## Re: cars on road

Your equation is correct. Add 16t to both sides. Subtract 200 from both sides. Divide both sides by 36. You wind up with $t = \dfrac{250}{36} \approx 6.94$.

3. ## Re: cars on road

Marko, can you not attach ONLY the problem,
and also make sure damn thing is readable.

Better still: type in the problem YOURSELF.

4. ## Re: cars on road

Originally Posted by markosheehan

can someone help me with question 8bii
i tried to solve this by 450-16t=200+20t t=4.16 the right answer is t =6.94
If you put t= 4.16 into 450- 16t= 200+ 20t you get 450- 16(4.16)= 383.44 while 200+ 20(4.16)= 283.2. No, 4.16 is NOT the correct answer.

I am inclined to suspect that you subtracted wrong. Subtracting 200 from 450 gives 250 but if you accidently got 150 rather than 250, 150/36= 4.17.

i get it now

6. ## Re: cars on road

if i type the question people will not get to see the diagram. Also for some questions its hard to type out the given question