a baseball fielder can throw a ball faster at low angles than high angles. this is modelled by assuming that at an angle a he can throw the baseball with a speed of k√(cosa) . where k is a constant. show the horizontal distance he can throw the ball is given by 2k^2/g *sina*√(cosa)

so i am using the equation ut-.5at^2=0 to find this. so i find what the time is when the vertical distance is zero. k√(cosa)sinat-.5gt^2

so time=2k√(cosa)sinat /g . i the sub this into the equation distance in the x direction=ut so

k√(cosa)cosa ( 2k√(cosa)sinat /g) is what i get but i dont think this is right