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Thread: particles.

  1. #1
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    particles.

    a stone is projected upwards vertically with initial speed u m/s a second stone is thrown upward from the same point with the same initial speed T seconds later than the first one. prove that they collide at a height of (4u^2-g^2t^2)/8g meters above the point of projection. to work this out i used uvast equations. for the first particle u=u s=h a=-g t= k for the second particle u=u s=h a=-g and t= k-t . the second particle has been in the air for t seconds less than the first particle thats why its time= k-t . k stands for the amount of time the first particle hhas been in the air. anyway i worked these out using s=ut+.5at^2. and i dont know where to go from here.
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  2. #2
    MHF Contributor
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    Re: particles.

    write down the 2 equations of motion and equate them and solve for $t$

    given $t$ use one of the equations to solve for the height.

    particles.-clipboard01.jpg
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