What resistance must be placed in parallel with a 156 resistor to make the equivalent resistance 115 ? in ohms. not sure what the equation is.
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Resistors in parallel: $\displaystyle \frac{1}{R_1} + ... + \frac{1}{R_{n}} = \frac{1}{R_{total}}$ So for you: $\displaystyle R_2 = \frac{1}{\frac{1}{115} - \frac{1}{156}} = 438$
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