A particle has a charge of +1.5 µC and moves from point A to point B, a distance of 0.15 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +8.50 x 10^-4 J.

(a) Find the magnitude and direction of the electric force that acts on the particle.

what is the magnitude in Newtons.

is the direction [along against or perpendicular]

(b) Find the magnitude and direction of the electric field that the particle experiences.

What is themagnitude in N/C

is the direction [along against or perpendicular]

---> I know the magnitude of two charges is: http://img144.imageshack.us/img144/5986/39653156ri3.png

where k is Coulumbs constant 9 x 10^9

can i use this equation to help me find the force?