One end of a meter stick is pinned to a table, so the stick can rotate freely in a plane parallel to the tabletop. Two forces, both parallel to the tabletop, are applied to the stick in such a way that the net torque is zero. One force has a magnitude of 4.00 N and is applied perpendicular to the stick at the free end. The other force has a magnitude of 6.00 N and acts at an angle θ = 68.3°, measured with respect to the stick. Where along the stick is the 6.00-N force applied? Express this distance with respect to the axis of rotation.
not sure why this wouldn't work, but i know that i could take the sin68.3 * 6.00 N to get the other sides, and Cos if i needed to.
i'm not sure how to find what i am looking for.