1. ## Functions Question

Hi, could I get some help with this question. I'm quite confused as to how to solve it using p as a function.

2. ## Re: Functions Question

Originally Posted by mathstahp
Hi, could I get some help with this question. I'm quite confused as to how to solve it using p as a function.
Well, the perimeter of the square is 72/2 = 36 inches = p. The sides of the square are thus p/4 = 36/4 = 9 inches. So what is the area of the square?

Similarly the circumference of the circle is 72/2 = 36 inches. Now recall the perimeter of the square: p = 36 inches. Thus C = 2 (pi) r = p.

Can you finish this?

-Dan

3. ## Re: Functions Question

Hi Dan!
Thanks a lot for the reply.
I still don't really get it though, I can't seem to get the answer given.

See:
Area of the square = (p/4)^2
r of the circle = p/2pi
Area of the circle = pi(p/2pi)^2

Is that correct so far? Thus A would be area of square + area of circle right? That's where I get stuck, cos I can't seem to get the answer from there.

Thanks again,
Eugene

4. ## Re: Functions Question

Originally Posted by mathstahp
Hi Dan!
Thanks a lot for the reply.
I still don't really get it though, I can't seem to get the answer given.

See:
Area of the square = (p/4)^2
r of the circle = p/2pi
Area of the circle = pi(p/2pi)^2

Is that correct so far? Thus A would be area of square + area of circle right? That's where I get stuck, cos I can't seem to get the answer from there.

Thanks again,
Eugene
That's right so far. So $\displaystyle A = (p/4)^2 + (pi)(p/(2 pi))^2$

I get A = 184 inches^2. What are you getting for it?

-Dan