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Math Help - Functions Question

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    Functions Question

    Hi, could I get some help with this question. I'm quite confused as to how to solve it using p as a function.Functions Question-math-question.png
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    Re: Functions Question

    Quote Originally Posted by mathstahp View Post
    Hi, could I get some help with this question. I'm quite confused as to how to solve it using p as a function.Click image for larger version. 

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    Well, the perimeter of the square is 72/2 = 36 inches = p. The sides of the square are thus p/4 = 36/4 = 9 inches. So what is the area of the square?

    Similarly the circumference of the circle is 72/2 = 36 inches. Now recall the perimeter of the square: p = 36 inches. Thus C = 2 (pi) r = p.

    Can you finish this?

    -Dan
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    Re: Functions Question

    Hi Dan!
    Thanks a lot for the reply.
    I still don't really get it though, I can't seem to get the answer given.

    See:
    Area of the square = (p/4)^2
    r of the circle = p/2pi
    Area of the circle = pi(p/2pi)^2

    Is that correct so far? Thus A would be area of square + area of circle right? That's where I get stuck, cos I can't seem to get the answer from there.

    Thanks again,
    Eugene
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    Forum Admin topsquark's Avatar
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    Re: Functions Question

    Quote Originally Posted by mathstahp View Post
    Hi Dan!
    Thanks a lot for the reply.
    I still don't really get it though, I can't seem to get the answer given.

    See:
    Area of the square = (p/4)^2
    r of the circle = p/2pi
    Area of the circle = pi(p/2pi)^2

    Is that correct so far? Thus A would be area of square + area of circle right? That's where I get stuck, cos I can't seem to get the answer from there.

    Thanks again,
    Eugene
    That's right so far. So A = (p/4)^2 + (pi)(p/(2 pi))^2

    I get A = 184 inches^2. What are you getting for it?

    -Dan
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