# Complex Analysis (A Few Clarifying Questions On Practice Problems)

• March 16th 2014, 10:09 AM
DrKittenPaws
Complex Analysis (A Few Clarifying Questions On Practice Problems)
I am having a few issues with Complex Analysis. I've done as much as I could on a few practice problems hoping I would understand it but I'm a bit stuck.

1) Find a parameterization of the line segment joining http://latex.codecogs.com/gif.latex?%5Csmall%202i and http://latex.codecogs.com/gif.latex?%5Csmall%201&plus;i. Find the image of the segment under the mapping http://latex.codecogs.com/gif.latex?...i%5Cbar%7Bz%7D.
This is what I did:
http://latex.codecogs.com/gif.latex?...%7D%20%3D%202i and http://latex.codecogs.com/gif.latex?...%3D%201&plus;i
http://latex.codecogs.com/gif.latex?...lus;z_%7B1%7Dt for http://latex.codecogs.com/gif.latex?...%20t%5Cleq%201
$=2i(1-t)+(1+t)i$
$=2i-2t+i-1$
$=3i-2it-1$
$f(z)=i(\bar{3i-2it-1})$
$=i(\bar{-1+3-2t)i})$
$=i(-1-(3-2t)i)$
$=i(-1-(3i-2it))$
$=i(-1-3i+2it)$
$=-i-3i^{2}+2i^{2}t$
$=-i+3-2t$ for $0\leq t \leq 1$

The graph doesn't look look right. I've reworked it a few times and I keep getting the same answer. Am I making a silly algebraic mistake somewhere?

2)Find the image $S'$ of the set $S$ under the given complex mapping $w=f(z)$
$f(z)=\bar{z}$; $S$ is the line $y=x$

A friend told me to do it this way:
$Re(z)=Im(z)$ $\therefore$ $w=\bar{z}=Re(z)=-Im(z)$
Is this correct?

I'll just submit the two problems I'm having the most problem with. Thanks for looking at this.

• March 16th 2014, 10:21 AM
romsek
Re: Complex Analysis (A Few Clarifying Questions On Practice Problems)
Quote:

Originally Posted by DrKittenPaws
I am having a few issues with Complex Analysis. I've done as much as I could on a few practice problems hoping I would understand it but I'm a bit stuck.

1) Find a parameterization of the line segment joining http://latex.codecogs.com/gif.latex?%5Csmall%202i and http://latex.codecogs.com/gif.latex?%5Csmall%201+i. Find the image of the segment under the mapping http://latex.codecogs.com/gif.latex?...i%5Cbar%7Bz%7D.
This is what I did:
http://latex.codecogs.com/gif.latex?...%7D%20%3D%202i and http://latex.codecogs.com/gif.latex?...7D%20%3D%201+i
http://latex.codecogs.com/gif.latex?...%29+z_%7B1%7Dt for http://latex.codecogs.com/gif.latex?...%20t%5Cleq%201
$=2i(1-t)+(1+t)i$
$=2i-2t+i-1$
$=3i-2it-1$
$f(z)=i(\bar{3i-2it-1})$
$=i(\bar{-1+3-2t)i})$
$=i(-1-(3-2t)i)$
$=i(-1-(3i-2it))$
$=i(-1-3i+2it)$
$=-i-3i^{2}+2i^{2}t$
$=-i+3-2t$ for $0\leq t \leq 1$

The graph doesn't look look right. I've reworked it a few times and I keep getting the same answer. Am I making a silly algebraic mistake somewhere?

2)Find the image $S'$ of the set $S$ under the given complex mapping $w=f(z)$
$f(z)=\bar{z}$; $S$ is the line $y=x$

A friend told me to do it this way:
$Re(z)=Im(z)$ $\therefore$ $w=\bar{z}=Re(z)=-Im(z)$
Is this correct?

I'll just submit the two problems I'm having the most problem with. Thanks for looking at this.

the parameterization of the segment is simply

$2\imath + (1-\imath)t~~0\leq t \leq 1$

try redoing the problem with this.
• March 16th 2014, 10:24 AM
DrKittenPaws
Re: Complex Analysis (A Few Clarifying Questions On Practice Problems)
Quote:

Originally Posted by romsek
the parameterization of the segment is simply

$2\imath + (1-\imath)t~~0\leq t \leq 1$

try redoing the problem with this.

Well, that was dumb of me. Let me try to work it out again and I'll get back to ya on what I got. Thanks!
• March 16th 2014, 12:53 PM
Deveno
Re: Complex Analysis (A Few Clarifying Questions On Practice Problems)
Quote:

Originally Posted by DrKittenPaws
I am having a few issues with Complex Analysis. I've done as much as I could on a few practice problems hoping I would understand it but I'm a bit stuck.

1) Find a parameterization of the line segment joining http://latex.codecogs.com/gif.latex?%5Csmall%202i and http://latex.codecogs.com/gif.latex?%5Csmall%201+i. Find the image of the segment under the mapping http://latex.codecogs.com/gif.latex?...i%5Cbar%7Bz%7D.
This is what I did:
http://latex.codecogs.com/gif.latex?...%7D%20%3D%202i and http://latex.codecogs.com/gif.latex?...7D%20%3D%201+i
http://latex.codecogs.com/gif.latex?...%29+z_%7B1%7Dt for http://latex.codecogs.com/gif.latex?...%20t%5Cleq%201
$=2i(1-t)+(1+t)i$
$=2i-2t+i-1$
$=3i-2it-1$
$f(z)=i(\bar{3i-2it-1})$
$=i(\bar{-1+3-2t)i})$
$=i(-1-(3-2t)i)$
$=i(-1-(3i-2it))$
$=i(-1-3i+2it)$
$=-i-3i^{2}+2i^{2}t$
$=-i+3-2t$ for $0\leq t \leq 1$

The graph doesn't look look right. I've reworked it a few times and I keep getting the same answer. Am I making a silly algebraic mistake somewhere?

2)Find the image $S'$ of the set $S$ under the given complex mapping $w=f(z)$
$f(z)=\bar{z}$; $S$ is the line $y=x$

A friend told me to do it this way:
$Re(z)=Im(z)$ $\therefore$ $w=\bar{z}=Re(z)=-Im(z)$
Is this correct?

I'll just submit the two problems I'm having the most problem with. Thanks for looking at this.

You should have $z_0(1 - t)$ and not $z_0(1 + t)$.

For your second problem, you have the elements on your line are complex numbers of the form: $z = x + ix$.

From this, we see that the images are of the form: $f(z) = \overline{z} = \overline{x+ix} = x - ix$, so that these lie on the line $y = -x$.
• March 16th 2014, 03:14 PM
Plato
Re: Complex Analysis (A Few Clarifying Questions On Practice Problems)
Quote:

Originally Posted by DrKittenPaws
I am having a few issues with Complex Analysis. I've done as much as I could on a few practice problems hoping I would understand it but I'm a bit stuck.
1) Find a parameterization of the line segment joining http://latex.codecogs.com/gif.latex?%5Csmall%202i and http://latex.codecogs.com/gif.latex?%5Csmall%201&plus;i. Find the image of the segment under the mapping http://latex.codecogs.com/gif.latex?...i%5Cbar%7Bz%7D.

Consider a vector approach. Express the points a vectors.
$(0,2)~\&~(1,1)\\(0,2)+t(1,-1),~0\le t\le 1\\(t,2-t),~0\le t\le 1\\t+i(2-t),~0\le t\le 1$
that is the parameterzation of the line segment.