I have a question about the Shift property of the Fourier Transform.
I understood that this is the property:
However, this doesn't really work for me when I apply it to Sin...
This is the Transform of Sin(t):
So according to the shift property, I would have expected to see this as the Transform of Sin(t-t0):
However, this is the actual transform of Sin(t-t0):
So the shift property doesn't work? What am I doing wrong?
Thank you (: