A particle of mass 3 kg, initially at position y(0) = 2 and moving with velocity v(0) = 4) is subject to the exponential driving force F(t) = 2e^(-3t)

Find an expression for y(t).

Any help would be greatly appreciated :)

Printable View

- Jan 31st 2013, 08:51 AMdom139Need help solving an equation of motion of type m x'' = F(t)
A particle of mass 3 kg, initially at position y(0) = 2 and moving with velocity v(0) = 4) is subject to the exponential driving force F(t) = 2e^(-3t)

Find an expression for y(t).

Any help would be greatly appreciated :) - Jan 31st 2013, 12:30 PMtopsquarkRe: Need help solving an equation of motion of type m x'' = F(t)
$\displaystyle m x" = F(t) = 2e^{-3t}$

So

$\displaystyle x" = \frac{1}{m} \cdot 2e^{-3t}$

What is the integral of $\displaystyle e^{-3t} $ ?

-Dan