How can I change polar coordinates z=7(cos(5pi/3)+isin(5pi/3)) into binomial form?
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How can I change polar coordinates z=7(cos(5pi/3)+isin(5pi/3)) into binomial form?
Hey franios.
What do you mean by binomial form? Is this something like (a+b)^n? What you can do is use z = re^(it) where t = 5pi/3 and then you can use the fact that e^(i5pi/3) = (e^(ipi/3))^5 which means (cos(pi/3) + isin(pi/3))^5 = (cos(5pi/3) + isin(5pi/3)).
It is almost in Binomial form as it is, just multiply through by 7 and evaluate the given trigonometric functions...Quote:
Originally Posted by franios
