How can I change polar coordinates z=7(cos(5pi/3)+isin(5pi/3)) into binomial form?

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- Sep 17th 2012, 06:49 PMfraniosComplex numbers
How can I change polar coordinates z=7(cos(5pi/3)+isin(5pi/3)) into binomial form?

- Sep 17th 2012, 11:56 PMchiroRe: Complex numbers
Hey franios.

What do you mean by binomial form? Is this something like (a+b)^n? What you can do is use z = re^(it) where t = 5pi/3 and then you can use the fact that e^(i5pi/3) = (e^(ipi/3))^5 which means (cos(pi/3) + isin(pi/3))^5 = (cos(5pi/3) + isin(5pi/3)). - Sep 18th 2012, 12:16 AMProve ItRe: Complex numbers