I am unable to get the right answer, closest answer : -0.01(r-1)
Trying again and again it keeps raising a lot more of other questions, that is simply boring for me.
Would be more than grateful if someone could kindly show me a detailed steps to the solution please.
(JF Talbert Textbook, Exercise 16D, Q.22)
For the function A=1/(r-1)^2 , a small change in r when r=2(r-1)^2 produces a 2% reduction in the value of A.
Find the approximate change in r.
(Given Answer: 0.01 increase)