• Oct 9th 2007, 12:38 AM
coopsterdude
• Oct 9th 2007, 12:44 AM
Jhevon
Quote:

Originally Posted by coopsterdude
so say you have $(r, \theta ) = (1, \pi)$
then that is the same as saying $(-1, 2 \pi) = (-1, 3 \pi) = (-1, 4 \pi) = ... = (-1, - \pi) = (-1, -2 \pi) = ...$ and so on.