A 1200kg mass rests on a track inclined at 30 degrees to the horizontal.
A force P inclined at 18 degrees TO THE TRACK (48 degrees to the horizontal) causes the carriage to move up the track at constant velocity (i.e. no acceleration). Coefficient of friction is 0.2; determine P. Use gravity as 9.8 ms^-1.
Constant velocity means no net forces act on the mass.
Parallel forces: Gravity = (m)(g)(sin30) = 5880N
Frictional force = (0.2)(Normal force)
That's all I've got so far :/
I wasn't taught this in my horrible school so I have only a rough idea of how to work these type of questions. Could you include all formulae used and just solve it for me? I can learn from the working.