# Math Help - Inverse Laplace Transform

1. ## Inverse Laplace Transform

Need help to solve the following:

Find the inverse Laplace transpose using convolution theorem:

$L^{-1} \left\{ \frac{s}{ $$s^2 + 4$$^3}\right\}$

Thanks.

2. ## Re: Inverse Laplace Transform

Let

$L^{-1} \left\{ \frac{s}{ $$s^2 + 4$$^3}\right\}=L^{-1} \left\{ \frac{s}{ $$s^2 + 4$$}\frac{1}{ $$s^2 + 4$$}\frac{1}{ $$s^2 + 4$$}\right\}=f(t)*g(t)*h(t)$

Then by the convolution theorem we can choose

$L^{-1} \left\{ \frac{s}{ $$s^2 + 4$$}\right\}=f(t)$

$L^{-1} \left\{ \frac{1}{ $$s^2 + 4$$}\right\}=g(t)=h(t)$

And you will find these inverse Laplace transforms on Wikipedia.