Can someone please tell me if the following looks correct:

Use Richardson Extrapolation to get an approximation to f'(0) of degree 1 higher than f'(0)=(f(h)-f(0)/h)

I've come up with

(( 4f(h/2) - f(h) - 3f(0)) / h ) - (kh^2) / 2 for constant k

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- November 10th 2011, 07:50 PMveronicak5678Richardson Extrapolation
Can someone please tell me if the following looks correct:

Use Richardson Extrapolation to get an approximation to f'(0) of degree 1 higher than f'(0)=(f(h)-f(0)/h)

I've come up with

(( 4f(h/2) - f(h) - 3f(0)) / h ) - (kh^2) / 2 for constant k - November 11th 2011, 06:45 AMCaptainBlackRe: Richardson Extrapolation