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Math Help - Inverse Laplace Transform

  1. #1
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    Inverse Laplace Transform

    I did the laplace transform of a function to end up with \frac{s-se^{-s-1}}{(s+1)(s^2+2s+1)}, but now I'm stuck. How would I go about finding the inverse laplace transform of that function?
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  2. #2
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    Re: Inverse Laplace Transform

    First step in doing the inverse, I think, would be to separate things out:

    \frac{s-se^{-s-1}}{(s+1)(s^2+2s+1)}=\frac{s}{(s+1)(s^2+2s+1)}-\frac{se^{-(s+1)}}{(s+1)(s^2+2s+1)}.

    The denominators all simplify considerably, don't they? Where does that lead?
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