# Math Help - Inverse Laplace Transform

1. ## Inverse Laplace Transform

I did the laplace transform of a function to end up with $\frac{s-se^{-s-1}}{(s+1)(s^2+2s+1)}$, but now I'm stuck. How would I go about finding the inverse laplace transform of that function?

2. ## Re: Inverse Laplace Transform

First step in doing the inverse, I think, would be to separate things out:

$\frac{s-se^{-s-1}}{(s+1)(s^2+2s+1)}=\frac{s}{(s+1)(s^2+2s+1)}-\frac{se^{-(s+1)}}{(s+1)(s^2+2s+1)}.$

The denominators all simplify considerably, don't they? Where does that lead?