
Fourier Transform
Hello Everyone!
I'm trying to find the Fourier transform of a sinc function without using the duality property. Here's what I got so far:\
$\displaystyle \mathcal{F} \{\frac{sin(\pi t)}{\pi t}\} = \int _R \frac{1}{\pi t} \cdot \frac{e^{i\pi t}  e^{i \pi t}}{2j} \cdot e^{i2\pi ft} dt$
Now let's not condier the complex exponentials out of the sine for now, include them later and make use fo the shifting property of the complex exponential.
$\displaystyle I= \int _R \frac{1}{\pi t} \cdot e^{i2\pi f t}dt = \int _R \frac{\cos (2\pi ft)}{\pi t}dt i \int _R \frac{\sin (2\pi ft)}{\pi t}dt $. Letting $\displaystyle x = 2\pi f t$ and eliminating the odd integral of $\displaystyle x$ we get $\displaystyle I = i\frac{1}{\pi} \int _R \frac{\sin(x)}{x} dx = i$.
So the integral $\displaystyle \int _R \frac{1}{2j} \cdot \frac{1}{\pi t} \cdot e^{i2\pi ft}dt = 1/2$. When adding the complex exponentials, we get this 1/2 shifted to the right and to the left by 1/2. What does that mean? Am I doing something wrong?
NB: I know the FT of a sinc is a rect

Re: Fourier Transform